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2019 WAEC GCE Mathematics Answers

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2019 WAEC GCE Mathematics Answers by : 2:07 pm On September 6, 2019

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Free WAEC GCE 2019 Mathematics Questions and Answers

Questions

WAEC GCE Mathematics Questions
WAEC GCE Mathematics Questions
WAEC GCE Mathematics Questions

WAEC GCE Mathematics Questions
WAEC GCE Mathematics Questions
WAEC GCE Mathematics Questions
WAEC GCE Mathematics Questions

Maths OBJ:
1-10: BBDCCBCBAA
11-20: BCBDCDBDDB
21-30: BCBDCBAACA
31-40: AABBDABCCB
41-50: BBBDBCBCDB

==COMPLETED==

OBJ QUESTIONS

WAEC GCE Mathematics OBJ Questions 1
WAEC GCE Mathematics OBJ Questions 1
WAEC GCE Mathematics OBJ Questions 2
WAEC GCE Mathematics OBJ Questions 2
WAEC GCE Mathematics OBJ Questions 3
WAEC GCE Mathematics OBJ Questions 4
WAEC GCE Mathematics OBJ Questions 4
WAEC GCE Mathematics OBJ Questions 5
WAEC GCE Mathematics OBJ Questions 5
WAEC GCE Mathematics OBJ Questions 6
WAEC GCE Mathematics OBJ Questions 6
WAEC GCE Mathematics OBJ Questions 7
WAEC GCE Mathematics OBJ Questions 7



Maths Theory
(1a)
Tabulate
X|2|3|4|5|7|
2|4|6|2|6|
3|6|1|7|5|
5|2|7|1|3|
7|6|5|3|1|

(1bi)
n=7,i;e 3 (*)7=5

(1bii)
n(*)n=1, n=3

WAEC GCE 2019 Mathematics Answers 1
WAEC GCE 2019 Mathematics Answers 1


(2a)
Given; slant height l = 18.7cm
Diameter, d = 24cm
π = 22/7
But, Curved surface area of cone = πrl
=π(d/2)l
= 22/7 × 24/2 × 18.7
=9873.6/14 = 705cm²

(2b)
128^x × 2/16^(1-x) = 8⅔x
= 2^7x × 2/2^4(1-x) = 2³(⅔x)
= 2^7x + 1/2^4(1-x) = 2^2x
Cross multiply
2^4(1 – x) + 2x = 2^7x + 1
4(1 – x) + 2x = 7x + 1
4 – 4x + 2x = 7x + 1
4 – 2x = 7x + 1
9x = 3
X = 3/9 = 1/3

WAEC GCE 2019 Mathematics Answers 2
WAEC GCE 2019 Mathematics Answers 2



(3a)
3√3/2 – 4√2/3 – √24
=3√3/2 – 4√2/√3 -√6*4
=(3√3/√2 × √2/√2) – (4√2/√3 × √3/√3) – 2√6
=3√6/2 – 4√6/3 – 2√6
=(3/2 – 4/3 – 2)√6
=(9 – 8 – 12)√6
= -11/6√6

(3bi)
prob(only one passes) = m passes and N fails or M fails and N passes
Prob (M passes) = 2/3; prob(M fails) = 1 – 2/3 = 1/3
Prob(N passes) = 4/5; prob(N fails) = 1 – 4/5 = 1/5
Prob(only one passes) = (2/3 × 1/5) + (1/3 × 4/5)
= 2/15 + 4/15
= 6/15
= 2/15

(3bii)
prob(at least one passes) = prob(only one passes) + prob(both parties)
= 2/5 + (2/3 × 4/5)
= 2/5 + 8/15
= 6/15 + 8/15
= 14/15

WAEC GCE 2019 Mathematics Answers 3
WAEC GCE 2019 Mathematics Answers 3



(4a)
17²=X²+15²
17²=X²+225
289-225=X²
64=X²
C=√64=8
Tanθ=18/15
Tanθ/1+2tanθ=18/15/1+2(8/15)=8/15/1+16/15
=8/15÷31/15=8/15*15/31=8/31

(4b)
Log^10/Log^64=½
Log10^10=Log10^64^½
y=√64=±8

WAEC GCE 2019 Mathematics Answers 4



(5a)
Obtuse Reflex
<MOP + <MOP = 360(angle at a point)
Obtuse <MOP + 196° = 360°
Obtuse <MOP = 360 – 196
= 164°

OMP + OPM + Obtuse MOP = 180°(<s in a triangle)
But OMP = OPM = x(radius of the circle and hence base angles are the same)

2x + 164 = 180
2x = 180 – 164
2x = 16°
X = 16/2 = 8°

Also MNP = 1/2×obtuseMOP
= 1/2 × 164°
= 82°

Now; MNP + NMP + NPM = 180° (<s in a triangle)
82 + (52+8) + (m+8) = 180°
m + 150 = 180°
M = 180 – 150
M = 30°

WAEC GCE 2019 Mathematics Answers 5
WAEC GCE 2019 Mathematics Answers 5

(5b)

WAEC GCE 2019 Mathematics Answers 5b
WAEC GCE 2019 Mathematics Answers 5b



(6a)
2^m*(1/8)^n = 128
2^m *2^-n = 2^7
m-3^n=7 ———(eq1)
4^m÷2^-4n=1/6
2^2m÷2^-4n=2-4
2m+4n=-4
m+2n=2 —–(eq2)
Subtract from (2)
m+2n-(n-3n)=-2-7
m+2n-m+3n=-9
5n/5=-9/5
n=-9/5
Sub for n in eq2
m+2(-9/5)=-2
m-18/5=-2
m=-2+18/5=8/5
;(m-n)=5/5-(-9/5)=17/5

(6b)
(-2,½) and (1-⅔)
y2-y1/x1-x2 = y-y1/x-x1
-⅔-½/1-(-2) = y-½/x-(-2)
-7/6/3=y-½/x+2
-7/18*y-½/x+2
(y-½)18=-7(x+2)
18y-9=-7x-14
18y=-7x-14+9
18y/18=-7x/18-5/18
y=-7x/18-5/18
18y=-7x-5

WAEC GCE 2019 Mathematics Answers 6
WAEC GCE 2019 Mathematics Answers 6



(8)
5th –> 11
8th –> 20
a + (n -1)d = 11
a + (5ˉ¹)d = 11
a + 4d = 11 –> (i)
a + 7d = 20 –> )ii)
a + 7d – a – 4d = 20 – 11
7d – 4d = 9
3d = 9
D = 9/3 = 3
D = 3
From eqn (i)
a + 4d = 11
a + 4 x 3 = 11
a + 12 = 11
a = 11 – 12
a = 1

WAEC GCE 2019 Mathematics Answers 8
WAEC GCE 2019 Mathematics Answers 8
(8ai)
Tn = a + (m-1)d
T₂ = -1 (12 – 1) 3
= -1 + 11 x 3
= -1 + 33
T12 = 32

(8aii)
Sn = n/2 [2a + (n – 1)d] = 12/2 [ 2 x (1) + 11 x 3] = 6 [ -2 + 33)
= 6 (31)
= 186



(9i) DRAW THE DIAGRAM

n (U) = 110
n (P) = 25
n (B) = 45
n (M) = 48
n (Pnm) = 10
n (Bnm) = 8
n (pnBnm) = 5

(9ii) for biology = 45 = 36

(9iii)
x + 14 + 1 + 5 + 5 + 36 + 3 + 35 = 110
x + 25 + 36 + 38 = 110
x = 110 – 99
x = 11

(9b)
15 = 22 + 18 + 2 x 1 + 10 +20/5
15 x 5 = 40 + 2x + 31
45 = 71 + 2x
45 – 71 + 2x
2x/2 = -26/2
X = 13
22, 18, 2x + 1, 10 , 20
For 2x (-B) +1 = -26 +1 = -25
22, 18, -25, 10, 20
-25, 10, 18, 20, 22
The media is 18



(10a)
Loan borrowed = 80/100 × 350,000
=280,000
Amount paid to the bank after 8 years = P + I
= P + PRT/100
=280000 + 280000×7×8/100
=280,000 + 156,800
Amount = #436,800

Total cost of house to the man = #350,000 + Interest
= #350,000 + 156,800
= #506,800

(10b)
Percentage increase in cost of house = 506,800 – 350,000 × 100%
= 156,800/350,000 × 100%
= 44.8%

(c) Percentage loss = loss/cost price × 100%
=(506,800 + 10,000) – 460,000/(506,800 + 10,000) × 100%
= 516,800 – 460,000/516,800 × 100%
56,800/516,800 × 100%
= 0.1099 × 100%
= 10.99%



(12)
Draw the diagram
x² = 20² + 8² – 2x 20 x 8 x Cos 50º
x² = 400 + 64 – 320 x 0.6427
x² = 464 – 205.7
√x² = √258.3
x = 16.1
x = 16km

(12ai)
TJ = 16km

(12aii)
sinØ/20 = sin50/16
sinØ = 20 x sin 50/16
sinØ 0.9576
Ø = sinˉ¹ 0.9576 = 73.3º
The bearing 90 -73.3 = 16.7º

(12b)
Draw the diagram
y = √12² + 5²
y = √144 + 25
y = √169 = 13
tan Ø = 5/12 = (0.04167)
Ø = tanˉ¹ (0.4167) = 22.6º
Sin Ø = 5/6 + x
Sin 22.6º = 5/6 + x
(0.3843) (6 + x) = 5
2.3058 + 0.3843x = 5
0.3843x = 5-2.3058
0.3843x/0.3843 = 2.6942/0.3943
X = 7.01
X ≈ 7



(13a)
Draw the diagram

(i) Extend DO to touch AB at M
AOD + AOM = 180°(<s on a straight line)
130 + AOM = 180°
AOM = 180 – 130 = 50°

Also;
BMO = BAO + AOM(Ext < = sum of two opposite interior <s of a triangle)
BMO = 26 + 50 = 76°
Also; ABD = 1/2AOD(angle at centre = twice angle at circum)
ABD = 1/2 × 130
=65°
Hence ODB + ABD + BMO = 180°(sum of <s in a triangle)
ODB + 65° + 76° = 180°
ODB = 180 – 141
= 39°

(ii) BOD + ODB + DBO = 180°(sum of <s in a triangle)
But ODB = DBO(base angles of an isosceles triangle)
BOD + 39° + 39° = 180°
BOD + 78° = 180°
BOD = 180 – 78 = 102°

(13b)
|1 2 6
3|1,3 2,3 (6,3)
4|1,4 2,4 (6,4)
5|1,5 2,5 (6,5)

prob (greater than 7) = 3/9 = 1/3

WAEC GCE 2019 Mathematics Answers 13
WAEC GCE 2019 Mathematics Answers 13

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