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Neco 2018 Physics Practical Questions and Answers – May / June Free Expo/ Runz

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Neco 2018 Physics Practical Questions and Answers – May / June Free Expo/ Runz by : 1:00 pm On June 4, 2018

Neco GCE 2018 Physics Practical Questions and Answers – Free Expo/ Runz

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2)
Tabulate
Cos @ – |75|65|55|45|35|
MO(cm)- |1.1|2.0|2.5|3.4|3.9|
NO(cm)- |6.2|6.4|6.6|6.8|7.2|
H=MO/NO- |0.177|0.313|0.379|0.500|0.542|
Cos @ – |0.2588|0.4226|0.5736|0.7071|0.8192|
2aix)
See No 2 Graph

.2bi)
Snell’s law is a formula used to describe the relationship between the
angles of incidence and refraction, when referring to light or other waves
passing through a boundary between two different isotropic media, such
as water, glass, or air.
i;e sini/sini=n
were n is known as refractive index
2bii)
given refractive index of glass =1.5
i;e a N g =1.5 (from air to glass)
sin C/sin90=gNa
sinC/sin90=1/aNg
sinC/1=1/1.5
since=0.6667
C=sin^-1(0.6667)
critical angle for glass,C =42degree
2biii)
i)I Ensured that the pins were vertical
ii)I Avoided parallax error when reading protractor.
CLICK
3)
ii) Vo=2.00V
3v)
Tabulate
S/N – |1|2|3|4|5|
R(n) – |2|3|4|5|6|
V(v) – 2.10|2.30|2.40|2.50|2.60|
R^-1(n^-1)- |0.500|0.333|0.250|0.200|0.167|
V^-1(V^-1)- |0.476|0.435|0.417|0.400|0.385|
3aix)
CLICK HERE FOR NO.3 GRAPH

3xi)
i)I ensured that the terminals were firmly tight to prevent partial contact
ii)I avoided parallax error when taking reading from the voltmeter.
3bi)
i)temperature of wire
ii)cross-sectional area of wire
iii)length of wire
iv)nature of wire
3bii)
effective E.M.F =2V (parallel connection)
effective internal resistance =rxr/r+r=r/2 n
current I =0.8A
external Resistance R =2n
using
E=I(R+r)
2=0.8(2+r/2)
2.5=(2+r/2)
2.5-2=r/2
0.5=r/2
r=0.5×2=1nh

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See the Previous Neco Physics Answers below
3aiii)
Vo=0.35V
TABULATE
S/N:1,2,3,4,5,6
R(ohm):1.0,2.0,3.0,4.0,5.0,6.0
V(v):1.40,1.65,1.80,2.00,2.10,2.15
R^-1(ohm^-1):1.000,0.500,0.333,0.200,0.167
V^-1(v^-1):0.714,0.606,0.556,0.500,0.476,0.465
3aiv)
DRAW THE GRAPH of V^-1(v^-1) against R^-1
3av)
Slope=change inV^-1/Change inR^-1
=(7.6-4.3)/(0.84-0.10)
3.3/0.74
=4.460
3avi)
Intercept=0.385
3avii)
I=0.385
I^-1=(0.385)^-1
=2.597
3aviii)
-I ensured tight connections
-I avoided error due to parallax when reading the voltmetre
-I ensured the key is opened after each reading to prevent the cell from running down
3bi)
The potential difference between two points in an electric circuit is the work done when a coulomb of charge passes between the points in an electric circuits
3bii)
E=I(R r)
where E=e.m.f of the cell
Therefore E=IR Ir=V Ir
Where :
V=IR=P.d lost across the external resistance of the cell
Ir=Pd lost across the internal resistance of the cell
E=e.m.f=workdone across external resistance of the cell

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