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Using Pythagoras theorem, l²=48² + 14² l²=2304 + 196 l²=2500 l=√2500 l=50m Area of Cone(Curved) =πrl Area of hemisphere=2πr² Total area of structure =πrl + 2πr² =πr(l + 2r) =22/7 * 14 [50 + 2(14)] =22/7 * 14 * 78 =3432cm² ~3430cm² (3 S.F)
(7b) let the percentage of Musa be x Let the percentage of sesay be y x + y=100 ——————-1 (x – 5)=2(y – 5) x – 5=2y – 10 x – 2y=-5 ——————-2 Equ (1) minus equ (2) y – (-2y)=100 – (-5) 3y=105 y=105/3 y=35 Sesay’s present age is 35years CLICK HERE FOR THE IMAGE
(8a) Let Ms Maureen’s Income = Nx 1/4x = shopping mall 1/3x = at an open market
Hence shopping mall and open market = 1/4x + 1/3x = 3x + 4x/12 = 7/12x
Hence the remaining amount = X-7/12x = 12x-7x/12 =5x/12
Then 2/5(5x/12) = mechanic workshop = 2x/12 = x/6 Amount left = N225,000 Total expenses = 7/12x + X/6 + 225000 = Nx
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