**WAEC 2017 Mathematics Theory and Obj Answers**

**Click Here to Enter Password**

MATHS OBJ:

1-10: CBBCCACBBC

11-20: CACBAAAADB

21-30: BBADBCCACB

31-40: BBCACBDADA

41-50: DDACCCDDCB

1a)

(y-1)log4=ylog16

log4^(y-1)=log16^y

log4^(y-1)=log4^2*y

y-1=2y

y=-1

1b)Distance =speed*time

let the time of the walk be x hours

=>4*(x 0.5)=5x

Because 30 minutes 0.5hours

4x 2=5x

5x-4x=2

x=2hours

=>5*2

=10km

2a)

2/3(3x-5)-3/5(2x-3)=3

2/3(3x-5)-3/5(2x-3)=3

lcm=15

=>(6x-10)/3-(6x-9)/9=3

Multiply both sides by 15

15(6x-10)/3-15(6x-9)5=15(3)

30x-50-3(6x-9)=45

30x-50-18x 27=45

12x-23=45

12x=45 23

x=68/12

x=5(2/3)

(2b)

=180-n-88=92-n

Also UTQ=180cm--(sum of 80 92-n 180-m=180(sum of 352-n-m=180

-n-m=180-352

-n-m=-172

-(n m)=-172

m n=172degrees

3a)

DRAW THE DIAGRAM

tanx=50/x

tan66.4=50/x

x=50/2.289

x=21.844m

x=22m

3b)

DRAW THE DIAGRAM

Area of=1/2*10*h=45

=>5h=45

h=45/5

h=9cm

Area of parallelogram=L*h

=9*6

=54cm^2

Therefore the area of QTUS=54 45

=99cm

4a)

Tnth=a (n-1)d

Snth=n/2[2a (n-1)d]
T6th=37

S6th=147

T6th=>37=a (6-1)d

=>37=a 5d-----(i)

S6th=>147=6/2[2a 96-1)d

=>147=3(2a 5d)

147=6a 15d------(ii)

Therefore a 5d=37----(i)

6a 15d=147-----(ii)

divide equation ii by 3

2a 5d=49--(ii)

multiply eq i by ii

=>a 10d=74

a 5d=49

5d/5=25/5

therefore d=5

substitute for d in eq i

a 5d=37

a 5(5)=37

a=37-25

a=12

The first term=12

4b)

Sn=n/2[2a (n-1)d]
S15=15/2[2(12) (15-1)5]
=15/2(24 (14*5)

=7.5(24 70)

=705

5a)

Let bag =B

shoe=S

U=120

n(BnS)=45,

n(S)=x 11

n(B)=x

n(SnB^1)=x 11-45

=x-34

n(BnS^1)=x-45

5b)

DRAW THE VENN DIAGRAM

x-45 45 x-34=120

2x-34=120

2x=120 34

2x/2=154/2

x=77

=11 x

=11 77=88

Therefore 88customers bought shoes

5c)

Pr(bag)=n(B)/U=77/120

(8a)

Tabulate:

X = 1,2,3,4,5

F = m 2, m-1, 2m-3, m 5, 3m-4 = 8m - 1

Fx = m 2, 2m-2, 6m-9, 4m 20, 15m-20 = 28m - 9

But x̄ ( this symbol (x̄) means X bar)

= 75/23

ΣFx / Σf = 75/23 = 28m - 9/8m-1

75/23 = 28m - 9/8m - 1

Cross multiply

75(8m-1) = 23(28m-9)

600m - 75 = 644m - 207

-75 207 = 644m - 600m

132 = 44m

M = 3

8b)

In tabular form

X = 1,2,3,4,5

F = 5,2,3,8,5

C*m Freq= 5,7,10,18,23

Q1 = (N 1/4) = (23 1/4)

= 6

Q3 = (3N 1/4) = (3*23 1/4)

= 18

Inter quarter range = Q3 - Q1

= 18-6

= 12

8bii)

Pr. (at least 4 mark)

= 8 3 2 5/23

= 18/23

10)

Sin x = 5/13

Using pythagoras rule

M^2 = 13^2 - 5^2 (^ means Raise to power)

M^2 = 169 - 25

M ^2 = 144

M = √144

M = 12

Hence:Cos x - 2sin x / 2tan x

12/13 - 2(5/13) / 2(5/12)

= 12/13 - 10/23 / 5/6

FIND LCM

= 12 - 10/13 / 5/6= 12/65

10b)

Draw a triangle LACB

in triangle LCB

Hyp^2 = Opp^2 Adj^2

12^2 = 9.6^2 |CB|^2

144 = 92.16 = |CB|^2

144 – 92.16 = |CB|^2

51.84 = |CB|^2

therefore, |CB| = √51.84

|CB| = 7.2m

|AC| |CB| =|AB|

|AC| 7.2m = 10m

|AC| = 10m – 7.2m

|AC| = 2.8m

In triangle LCA

Hyp^2 = Opp^2 Adj^2

|LA|^2 = |AC|^2 |LC|^2

|LA|^2 = 2.8^2 9.6^2

|LA|^2 = 7.84 92.16

|LA|^2 =100

|LA| = √100

|LA| = 10m

10bii)

in triangle LCA

sinθ = Opp/Hyp

sinθ = |LC|/|LA|

sinθ = 9.6/10

sinθ = 0.96

θ = sin^-1 (0.96)

θ = 73.74

13ai)

given

x(*)y=x y/2

3(*)2/5=3 2/5/2

=(15 2/5)*1/2

=17/5*1/2

=17/10= 1,7/10

13aii)

8(*)y=8^1/4

=8 y/2 =33/4

32 4y=66

4y=66-32

4y=34

y=34/4

y=17/2

y=8^1/2

13b)

given DABC

AB=(^-4/6) and AC =(3/^-8)

so AP =1/2(^-4/6)

AP=(^-2/3)

hence

CP = CA AP

CP= -(3/^8) (^-2/3)

CP = (^-5/11)

9ai)

DRAW THE DIAGRAM

9aii)

RTS=?

PTS=180-65(Sum of9b)

Therefore tita=180-52-32-70(sum of < in a triangle)

tita=20degrees

Therefore LWYZ=20 degrees

**Take Our Free Runz**: WAEC 2017 Mathematics Theory and Obj Answers will be posted here for free but 60 minutes after exam starts.

**Take Our Paid Runz**: With N500 we will send you the password to view the answers 6Hrs before exam starts. Call 09067385575 for payment details

Refresh this page 60 minutes after exam starts for free answers.

**Click Here to Refresh**

### Like this:

Like Loading...

*Related*

### Publication author

7
I am the brain behind Earboard.com

Comments: 41Publics: 581Registration: 13-02-2017
pls math question and answer 2morrow

please don’t waste time to post 2morow answers please

Pls I nid it pls 4 free plssssssss

pls, send it fast ooooo

Please Reduce The Time For Posting Free Answer