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WAEC 2021 Further Mathematics Theory and Objective Answers /Expo |
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WAEC 2021 Further Mathematics Theory and Objective Answers /Expo by Blogger: 1:06 am On August 2, 2021 |
WAEC 2021 Further Mathematics exam will be holding on 9th May, 2019. As we have been doing for other exams, we are here to help you with the Further Mathematics Theory and Objective Answers. Most importantly, you should subscribe to Earboard.com Waec Runz so that you get correctly solved answers to the Further Mathematics questions. For those who have paid for our runz, click the button below to see the answers. For those who have not subscribed, read further to know how to subscribe! Take Our Paid Runz: With N400 we will send you the password to view all the answers 3 hours before exam starts. To make payment, simply buy MTN Recharge card of N400 and send the pin to 09067385575 . You can also do transfer to the number or contact us for our bank details. Benefits of Paid Runz
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Past WAEC Further Mathematics Answers1-10DCADBCCDCC THEORY (1) X-3(12-2x+8)+4(30-5x-4)+3(-20-4) = -24 (2) (3a) (3b) No 4 5)x-8,5,1,7,2,6,3,4 Coefficient of Correlation = ∑xy / √(∑x²∑y²) Where: x = (X – Mean) y = (Y – Mean) Data table Mean of the set of Data for X = ∑X / N ∑X = 8 + 5 + 1 + 7 + 2 + 6 + 3 + 4 ∑X = 36 Mean of the set of Data for X = 4.5 Mean of the set of Data for Y = ∑Y / N ∑Y = 6 + 3 + 4 + 8 + 5 + 7 + 1 + 2 ∑Y = 36 Mean of the set of Data for Y = 36 / 8 Mean of the set of Data for Y = 4.5 From the Data Analysis we have: ∑xy = 5.25 + -0.75 + 1.75 + 8.75 + -1.25 + 3.75 + 5.25 + 1.25 ∑xy = 24 ∑x² = 12.25 + 0.25 + 12.25 + 6.25 + 6.25 + 2.25 + 2.25 + 0.25 ∑x² = 42 ∑y² = 2.25 + 2.25 + 0.25 + 12.25 + 0.25 + 6.25 + 12.25 + 6.25 ∑y² = 42 starlight Coefficient of Correlation = 24 / √(42 x 42) Coefficient of Correlation = 24 / √(1764) Coefficient of Correlation = 24 / 42 Coefficient of Correlation = 0.5714 (6) Hence, = (1/3 × 4/5) + (1/5 × 2/3) ==================================== (7) Therefore: ============================ (a) (b)
(9) radius is the same hence Taking the second pair (a) coordinates of centre is (11/6, -31/18) (b) Radius r = √(y-2)²+(x-3)² (c) (X – 11/6)² + (y + 31/18)² = 3.9² |
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