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WAEC 2019 Physics Practical Expo Questions and Answers – Free Runz / Runs

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WAEC 2019 Physics Practical Expo Questions and Answers – Free Runz / Runs by : 4:11 am On April 4, 2018

WAEC 2019 Physics practical exam will be holding on 2nd May, 2019. As we have been doing for other exams, we are here to help you with the Physics practical answers. For science students, practical is a very important exam because they carry a lot of marks. There is a saying that any student who has passed practical, has already passed the theory and obj part of the exam and vise versa. To some extent, this is true. If you do well in this Physics practical, you have got 40% chance of crediting your Physics paper. Because of this, you should be very serious with the exam. Most importantly, you should subscribe to Earboard.com Waec Runz so that you get correctly solved answers for the Physics practical exam.

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Thursday 2nd May, 2019

Physics 3 (Practical) (Alternative A) – 09:30 a.m. – 12:15 p.m. (1st Set)
Physics 3 (Practical) (Alternative A) – 12:40 p.m – 3:25p.m. (2nd Set)

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(1aviii)
In a tabular form
Under y(cm)
20.0, 30.0, 40.0, 50.0, 60.0
Under t(s)
36.61, 33.66, 31.32, 28.62, 25.93
Under T = t/20(s)
1.8305, 1.6830, 1.5660, 1.4310, 1.2965
Under T²(s²)
3.3507, 2.8325, 2.4524, 2.0478, 1.6809
(1ax)
Slope s = ΔT²/Δy
S = 4 – 2.5/0 – 39
S = 1.5/-39
S = -0.0385
Intercept, C = 4.0
(1axi)
SR = c
R = c/s = 4/-0.0385 = -103.9
(1axii)
(i) I ensured that the retort stand was well clamped.
(ii) I avoided error due to parallax when reading the metre rule.

=======================================
(3ai)
E.m.f, E = 3.00v
(3avii)
In a tabular form
Under R(ohms)
2.0, 5.0, 10.0, 12.0, 15.0, 20.0
Under V(v)
0.86, 0.62, 0.43, 0.38, 0.32, 0.25
Under V-¹(v-¹)
1.1628, 1.6129, 2.3256, 2.6316, 3.1250, 4.0000
(3aix)
Slope s = ΔR/Δv-¹
=17.5 – 4.25/3.5 – 1.5
=13.25/2
=6.625
Intercept, C = -5.75
(3ax)
S = Roα
6.625 = 0.85(α)
α = 6.625/0.85 = 7.79
C = -(Ro + β)
= -5.75 = -(0.85 + β)
β = 5.75 – 0.85
β = 4.9
(3axi)
(i) I ensured tight connections.
(ii) I avoided error due to parallax when reading the voltmeter.
(3bi)
Vab = 12 – 8 = 4v
Rab = 4×5/4+5 = 20/9ohms
Iab = Vab/Rab = 4/20/9 = 4 ×9/20 = 9/5
=1.8A
Power = I²ab Rab
=1.8² * 20/9
= 7.2watts
(3bii)
Current in line = power/voltage = 3600/240
=15A
Circuit breaker remain closed because current in line is less than 20A

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3 comments

  1. prosper

    1)
    Tabulate
    S/n 1,2,3,4,5
    L(cm) 90.00,80.00,70.00,60.00,50.00
    T(s) 38.30,35.40,33.40,29.60,27.50
    T=t/20(s) 1.92,1.77,1.67,1.48,1.38
    sqrL(cm^1/2) 9.49,8.94,8.37,7.75,7.07
    1vii)
    CLICK HERE FOR THE GRAPH IMAGE
    1ix)
    slope (s) = D vertical/D horizontal
    = 1.90-155/9.49-775
    =0.35/1.75
    s=0.201
    1x)
    g=4^2/s^2
    =4*(3.142)^2/(0.201)^2
    =977.4cm1s^2
    1xii)
    -precautions-
    Take Any Two
    i)I avoided conical oscillation
    ii)I avoided drought
    iii)I avoided parallax error in taking reading from the metre rule
    iv)I avoided zero error in taking reading from the stop watch
    MORE COMING…
    3)
    Tabulate
    3)
    -precautions-
    take any two
    i)I removed key when reading is not taking
    ii)I ensured tight connections at the terminals
    iii)I avoided parallax error when taking reading from the
    ammeter.
    3bii)
    i)length – longer wires have greater resistance.
    ii)thickness – smaller diameter wires have greater resistance.
    SOLVING AND TYPING…

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