Earboard Logo

Welcome, Guest: Join Earboard Forum / LOGIN! / Create New Post / Contact Us
Stats: 43768 members, 38289 posts. Date: Sunday, 16th February 2025

2025/2026 WAEC GCE Physics Theory and Obj Answer - Education - Earboard

(1) (Reply) (Create New Posts) (Go Down)

2025/2026 WAEC GCE Physics Theory and Obj Answer by : 1:50 am On January 9, 2025

The 2025 WAEC GCE Physics Theory and Objective Questions and Answers are available on EARBOARD now. Please, click on the button below to enter the password sent you by the admin.

Take Our Free Runz: The 2025 WAEC GCE (First Series) Physics theory and obj Answers will be posted here for free but 60 minutes after exam starts.
Take Our Paid Runz: With N400, we will send you the password to view all the answers 3 hours before the exam starts. To make the payment, simply buy MTN Recharge card of N400 and send it to 09067385575 . You can also do transfer to the number.

How to send the card: Type the card pin, your subjects & phone number and send to 09067385575. You can also call or message the above number for more details.

Why we are the best? We give you 24/7 customer support. We offer the cheapest Runz (N400 per Subject, N2000 for 5-9 Subjects and N6000 for all our runz). Our answers are real and genuine. We also give free Runz to candidates who cannot afford our paid Runz. Where else on the internet can you get this kind of service? Subscribe now and enjoy while it lasts!

Past WAEC GCE 2025 Physics Theory and OBJ Answers

WAEC LOGO
WAEC Official Logo

Physics OBJ:
1-10: ABABDBBBBC
11-20: BDCDADCABA
21-30: BCBCADDACD
31-40: ADBCDACBBB
41-50: BDAACAABCA

(1)
(a)
Horizontal speed just before it strikes floor = ucosθ
= 10cosθ * 1.0
= 10 m/s

(b)
t = √(2g/h)
= √(2*10*1)
= √20
= 4.47s

(2)
(i)cutting through materials,such as metal.
(ii)burning,eg laser engraving.
(iii)It is used to destroy damaged tissue or to stop bleeding, eg after surgery.

(3)
(i)Iron
(ii) Nickel
(iii) Cobalt

(4a)
Given: u = 20m/s
t = 4s
g = 10m/s²
h = ?
Using s = ut – ½gt²
s = 20(4) – ½(10)(4)²
s = 0m

(b)
The inference is that after 4s, the ball returns back to the plane of projection

(5)
(i) Cost
(ii) Temperature Co-efficient
(iii) Size and Watts Capacity.

(8ai)
Force is a push or pull which changes a body’s state of rest or uniform motion in a straight line.

(8aii)
(i) field force
(ii) contact force

(8bi)
Bodies are designed to move through fluid streamlined in shape so as to oppose or overcome the motion of the fluid

(8bii)
(i) fish
(ii) submarine

(8ci)
Mass= 1.3 kg
F= 1.2 m
V= 7.0 m/s

[Diagram]

(8cii)
(a) Acceleration
Note , V²= U² + 2as
Where S=r=1.2 m
(7.0)²= 0²+2× a (1.2)
= 49/2.4 = 2.4a/2.4
a = 20.4

(b)
Force=?
From force = MA
Force =1.3×20.4
Force =25.52

(9a)
(i) Coat (Trapped air in between the fabric)
(ii) The hair and the fur of animals are bad conductors of heat and they protect them from cold .

(9b)
-Renewable: Water, corn stalk
-Non-renewable: coal, natural gasgas

(9c)
A closed is a physical system so far removed from other systems that it does not interact with them.

(9d)
Heat required to melt = mc∆ + ml
NB: Not sure of the temperature given, if it is -3°C or -5°C, However, Using -3°C
Heat = (0.1×2200×3)+(0.1×2.26×10^6)
= 226660 J

(9ei)
Given: 75 heart beats in 1 min
Therefore in 1 hour, we have (75×60) heart beats = 4500 heart beats
Also given: 2J of energy is expended in 1 heart beat
Therefore for 4500 heart beats, energy expended = (4500×2) J = 9000J

(9eii)
Energy = mc∆
9000 = (0.25×4200×∆)
9000 = 1050∆
∆ = 9000/1050
Temperature rise = 8.57°C

(10a)
(i) Plane waves
(ii) Spherical waves
-For plane waves -Their dipper are wooden strip
-For spherical wave – Their dipper are spherical ball

(10b)
White and are actual colours of light because both white and black are centralof additive and substractive

(10c)
A yellow object is illuminated with green liight and when viewed through a yam filter becomes white since the colours consist of both primary and secondary colours which are known as complementary colours

(10d)
f0=V/2l
2f0l=V
l=V/2f0
=330/(2*400)
l=330/800
0.41m

(10e)
f=200khz
Period T=1/f
T=(1/200*10^3)s
Period T=5*10^-6s

(11a)
(i) Electrical method
(ii) Contact method

(11b)
Electric lines of force are imaginary lines drawn in an electric field in such a way that the direction at any point gives the direction of the electric field at such a point

(11c)
QR = SP

(11d)
Resistivity is the resistance of a unit length of material of unit cross-sectional area

(11d)
Heat required to melt = mc∆ + ml
NB: Not sure of the temperature given, if it is -3°C or -5°C, However, Using -3°C
Heat = (0.1×2200×3)+(0.1×2.26×10^6)
= 226660 J

(11e)
Given: F = 50Hz
L = 10 mH (10×10^-³H)
Inductive reactance, XL = 2πFL
= 2×3.14×50×10×10^-³
= 3.14 ohms

(11f)
If voltmeter reads 12V, over the 500 ohms, then using I = V/R
current in the circuit is I = 12/500
I = 0.024A
Hence over the 200 ohms, V = IR
V = 0.024×200
V = 4.8 VOLTS
Voltmeter will read 4.8 volts

WAEC GCE 2025 | WAEC GCE 2026 | WAEC GCE 2024/2026 | WAEC GCE 2025

About Flex

I am a verified author at EARBOARD.com... For any complaint or information, contact EARBOARD admin on 09067385575

Tags: ,

One comment

Leave a Reply

(1) (Reply)

WAEC 2025/2026 May/June Registration Deadline / 2025/2026 WAEC Practical and Physical Geography Answers / WAEC 2025 Literature in English (Drama and Poetry) Answers /

(Go Up)



Earboard Forum - Copyright @ 2016 - 2025. All rights reserved. See How To Advertise. DMCA Content Removal.
Disclaimer: Every member is solely responsible for anything that he/she posts or uploads on Earbaord.